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Problem :-No Idea in python - Hacker Rank Solution

There is an array of  integers. There are also  disjoint sets,  and , each containing  integers. You like all the integers in set  and dislike all the integers in set . Your initial happiness is . For each  integer in the array, if , you add  to your happiness. If , you add  to your happiness. Otherwise, your happiness does not change. Output your final happiness at the end.

Note: Since  and  are sets, they have no repeated elements. However, the array might contain duplicate elements.

Constraints :-

Input Format :-

The first line contains integers  and  separated by a space.
The second line contains  integers, the elements of the array.
The third and fourth lines contain  integers,  and , respectively.

Output Format :-

Output a single integer, your total happiness.

Sample Input :-

3 2

1 5 3

3 1

5 7

Sample Output :-

1

Explanation :-

You gain  unit of happiness for elements  and  in set . You lose  unit for  in set . The element  in set  does not exist in the array so it is not included in the calculation.

Hence, the total happiness is .

Solution :-

n,m=input().split(" ")

b=list(map(int,input().split()))

c=set(map(int,input().split()))

d=set(map(int,input().split()))

a=0

for i in b:

   

    if i in c:

        a=a+1

    elif i in d :

        a=a-1

print(a)   

        

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